(完整word版)2018年高考南通市数学学科基地密卷(9).pdf

高三数学试卷第 1 页 共 20 页（第 3 题）2018 年高考模拟试卷（9）南通市数学学科基地命题第卷（必做题，共160分）一、填空题：本大题共14 小题，每小题5 分，共 70 分1 设集合 A=1，x，B=2，3，4，若 AB=4，则 x 的值为 2 若复数 z12+i，z1z2()2z5，则 z2 3 对一批产品的长度（单位：毫米）进行抽样检测，样本容量为200，右图为检测结果的频率分布直方图，根据产品标准，单件产品长度在区间25，30）的为一等品，在区间20，25）和30，35）的为二等品，其余均为三等品，则样本中三等品的件数为 4 执行如图所示的流程图，会输出一列数，则这列数中的第3 个数为 5 为活跃气氛，某同学微信群进行了抢红包活动某同学发了一个“长长久久”随机分配红包，总金额为9.9 元，随机分配成5 份，金额分别为2.53 元，1.19 元，3.21 元，0.73 元，2.33 元，则身处海外的两名同学抢得的金额之和不低于5 元的概率为 6 函数22log(32)yxx的值域为 7 已知 PABC 是正三棱锥，其外接球O 的表面积为16，且 APOBPO CPO 30，则三棱锥的体积为 8 已知双曲线2214yx的左、右顶点为A、B，焦点在y轴上的椭圆以A、B 为顶点，且离心率为32，过 A 作斜率为k的直线l交双曲线于另一点M，交椭圆于另一点N，若ANNMuuu ru uu u r，则k的值为 （第 4 题）精品资料-欢迎下载-欢迎下载 名师归纳-第 1 页，共 20 页 -高三数学试卷第 2 页 共 20 页9 已知函数f(x)cosx(sin xcosx)12，若2()6f，则cos(2)4的值为 10已知na是首项为1，公比为 2 的等比数列，数列nb满足11ba，且12nbaaL1121nnnaaaaaL（2,nnN），若(28)2018mmab，则m的值为11定义在1,1上的函数()sin(1)f xxaxb a的值恒非负，则ab的最大值为 12在ABC中，若352115CA ABAB BCBC CAuu u r uuu ruu u r uuu ruuu r uu u r，则cosC的值为 13在平面直角坐标系xOy中，圆O：221xy，直线:l30 xay，过直线l上一点Q作圆 O 的切线，切点为,P N，且23QP QNuu u r u uu r，则正实数a的取值范围是 14已知偶函数()yf x满足(2)(2)f xfx，且在2,0 x时，2()1f xx，若存在12nxxxL，满足120nxxxL，且1223fxfxfxfxL12017nnfxfx，则nx最小值为 二、解答题：本大题共6 小题，共计90 分15（本小题满分14分）已知函数()sin0,0f xAxA的最小值是 2，其图象经过点(,1)3M（1）求()f x的解析式；（2）已知,(0,)2，且8()5f，24()13f，求()f的值精品资料-欢迎下载-欢迎下载 名师归纳-第 2 页，共 20 页 -文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3文档编码:CQ4N5B8T7F7 HR7Y3K3E5X6 ZP1O5I10F9L3高三数学试卷第 3 页 共 20 页A B O D（第 17 题）16（本小题满分14 分）如图，在四棱锥PABCD中，90BAD，ADBC，2ADBC，ABPA（1）求证：平面PAD平面ABCD；（2）若E为PD的中点，求证：CE平面PAB17（本小题满分14 分）有一块以点O 为圆心，半径为2 百米的圆形草坪，草坪内距离O 点2百米的 D 点有一用于灌溉的水笼头，现准备过点D 修一条笔直小路交草坪圆周于A，B 两点，为了方便居民散步，同时修建小路OA，OB，其中小路的宽度忽略不计（1）若要使修建的小路的费用最省，试求小路的最短长度；（2）若要在ABO区域内(含边界)规划出一块圆形的场地用于老年人跳广场舞，试求这块圆形广场的最大面积(结果保留根号和)18（本小题满分16 分）如图，点128nnaa，nb，nS分别为椭圆2214+25nnnbbS的左、右顶点和右PABCDE（第 16 题）精品资料-欢迎下载-欢迎下载 名师归纳-第 3 页，共 20 页 -文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 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ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9高三数学试卷第 4 页 共 20 页xyOFABMN（第 18 题）焦点，过点nN的直线na（异于nb轴）交椭圆C于点nb，nnncab（1）若3AF，点4rst，与椭圆C左准线的距离为5，求椭圆C的方程；（2）已知直线()rst的斜率是直线rst，斜率的()()f mxf x倍 求椭圆C的离心率；若椭圆C的焦距为()()f mxf x，求 AMN 面积的最大值19（本小题满分16 分）已知函数2()lnfxxxax（1）若曲线()yf x在1x处的切线过点(22)A，求实数a的值；设函数()()f xg xx，当0s时，试比较()g s与1()gs的大小；（2）若函数()f x有两个极值点1x，2x（12xx），求证：11()2f x20（本小题满分16 分）设数列na的各项均为不等的正整数，其前n项和为nS，我们称满足条件“对任意的*mnN，均有()()()n mnmnm SnmSS”的数列na为“好”数列精品资料-欢迎下载-欢迎下载 名师归纳-第 4 页，共 20 页 -文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9高三数学试卷第 5 页 共 20 页（1）试分别判断数列na，nb是否为“好”数列，其中21nan，12nnb，*nN，并给出证明；（2）已知数列nc为“好”数列 若20172018c，求数列nc的通项公式；若1cp，且对任意给定正整数ps，（1s），有1stccc，成等比数列，求证：2ts2018 年高考模拟试卷（9）数学(附加题)21【选做题】本题包括A、B、C、D 四小题，请选定两题，并在相应的答题区域内作答A选修 41：几何证明选讲（本小题满分10 分）如图，AB 为 O 的直径，BD 是O 的切线，连接AD 交 O 于 E，若 BDCE，AB 交 CE 于 M，求证：2ABAE ADB选修 42：矩阵与变换 （本小题满分10 分）已知点A在变换T:2xxxyyyy作用后，再绕原点逆时针旋转90，得到点B若点B的坐标为(3 4)，求点A的坐标MEDCBA（第 21-A）精品资料-欢迎下载-欢迎下载 名师归纳-第 5 页，共 20 页 -文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9高三数学试卷第 6 页 共 20 页C选修 44：坐标系与参数方程（本小题满分10 分）在极坐标系中，圆C 的方程为2 cos(0)aa，以极点为坐标原点，极轴为x轴正半轴建立平面直角坐标系，设直线l的参数方程为31,(43xttyt为参数），若直线l与圆 C恒有公共点，求实数a的取值范围D选修 45：不等式选讲 （本小题满分10 分）已知正数,a b c满足2362abc，求321abc的最小值【必做题】第22 题、第 23 题，每题10 分，共计 20 分请在答卷纸指定区域内作答22 已知直三棱柱111ABCA B C中，ABC为等边三角形，延长1BB至M，使11BBB M，连接11,A M AC CM，若190MA C（1）求直线1C M与平面1CA M所成角的正弦值；（2）求平面1CA M与平面11AAC C所成的锐二面角23（本小题满分10 分）（1）求证：11()kkn kn kkCnk C；（2）求证：100820170(1)120172017nnnnCnMC1B1A1C BA（第 22 题）精品资料-欢迎下载-欢迎下载 名师归纳-第 6 页，共 20 页 -文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9高三数学试卷第 7 页 共 20 页2018 年高考模拟试卷（9）参考答案数学一、填空题：1【答案】4【解析】因为A B=4，所以 4A，故 x42【答案】2+i【解析由z1z25，得z252+i2i，所以 z12+i3【答案】50【解析】三等品总数1(0,050.03750.0625)520050n4【答案】30【解析】3A，1N，输出 3；6A，2N，输出 6；30A，3N，输出 30；则这列数中的第3 个数是 305【答案】15【解析】两名同学抢红包的事件如下：（2.53，1.19）（2.53，3.21）（2.53，0.73）（2.53，2.33）（1.19，3.21）（1.19，0.73）（1.19，2.33）（3.21，0.73）（3.21，2.33）（0.73，2.33），共 10种可能，其中金额不低于5 元的事件有（2.53，3.21）（3.21，2.33），共 2 种可能，所以不低于 5 元的概率21105P6【答案】,2【解析】因为2232(1)40,4xxx，所以22log(32),2xx，即值域为,2 7【答案】934【解析】设球的半径为R，ABC 的外接圆圆心为O，则由球的表面积为16，精品资料-欢迎下载-欢迎下载 名师归纳-第 7 页，共 20 页 -文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 ZF3E4S4X10Q9文档编码:CB6J2Y7T4F6 HK6B6P8K6O4 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